I am using an array of strings inside my function declared like this
char (*array)[PATH_MAX] = malloc (1000 * sizeof *array);
Allocating 1000 char pointers of size PATH_MAX
(1024).
I want the function to return that specific data structure, i.e. return the pointer array
. But I can't manage to choose the correct return type.
warning: returning 'char (*)[1024]' from a function with return type 'int' makes integer from pointer without a cast [-Wint-conversion]
I get that I can't have int
as return type, but char**
doesn't work either.
warning: returning 'char (*)[1024]' from a function with incompatible return type 'char **' [-Wincompatible-pointer-types]
I've tried using char (*)[1024]
as return type, but it gives me generic C error messages, leading me to believe that I am not using the correct syntax.
error: expected identifier or '(' before ')' token
38 | char (*)[1024] read_dir (char *path) {
| ^
Is there a correct syntax for achieving this or am I just doing it wrong?
Time for typedef
typedef char arr1k_char[1000];
arr1k_char *foo(int n) {
arr1k_char *x = malloc(n * sizeof *x);
return x;
}