print(array.sort())
return array.sort()
print or return an empty array =
[]
while if I do this
array.sort()
print(array)
OR
array.sort()
return array
Gives me a sorted array =
[1, 4, 9, 10]
Why is it like this I tried understanding the working of the inbuilt code for sorting but couldn't understand? Is it a memory problem or something else?
sort
sorts the array and returns None
. For example:
>> a1 = [1, 9, 10, 4]
>> a1.sort()
>> print(a1)
[1, 4, 9, 10]
On the other hand, sorted
returns a sorted copy of the original array, but the original array remains unsorted.
>> a2 = [1, 9, 10, 4]
>> print(sorted(a2))
[1, 9, 10, 4]
>> print(a2)
[1, 4, 9, 10]