I am working on a leetcode problem where I am asked to check whether or not a Binary Search Tree is valid. So far, my solution only passes 58 out 75 test cases. Any pointers on where I went wrong and how to fix it?
Here is the question:
Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greater than the node's key. Both the left and right subtrees must also be binary search trees.
Example 1:
2
/ \
1 3
Input: [2,1,3]
Output: true
Example 2:
5
/ \
1 4
/ \
3 6
Input: [5,1,4,null,null,3,6]
Output: false
Explanation: The root node's value is 5 but its right child's value is 4.
Here is my Solution:
class Solution {
public boolean isValidBST(TreeNode root) {
return isValidHelper(root);
}
public boolean isValidHelper(TreeNode root)
{
if(root == null)
return true;
isValidHelper(root.left);
if(root.left != null && !(root.left.val < root.val) || root.right != null && !(root.right.val > root.val))
return false;
isValidHelper(root.right);
return true;
}
}
Your program fails in cases like this:
5
3 7
1 6
because you only compare the value at the root of the subtrees.
I don't give a fix on purpose. You will learn more finding that out yourself.