public class Programma {
public static void main(String args[]) {
int array[] = { 1, 2, 4, 5, 6, 7, 8 };
int v = 4;
int first = 0;
int last = 6;
if (binary_search(array, v, first, last) == 1) {
System.out.println("Value " + v + " found!");
} else {
System.out.println("Value " + v + " not found.");
}
}
static int binary_search(int array[], int v, int first, int last) {
if (first > last) {
return 0;
}
int m = (first + last) / 2;
System.out.println("Actual m is: " + m + " of " + first + last);
if (array[m] == v) {
return 1;
} else if (v > array[m]) {
binary_search(array, v, m + 1, last);
} else {
binary_search(array, v, first, m - 1);
}
return -1;
}
}
Output is:
Actual m is: 3 of 06
Actual m is: 1 of 02
Actual m is: 2 of 22
Value 4 not found.
I really don't understand why the first
and the last
become from 06 to 02, when they should become 46, since 3 is smaller than 4.... I added the condition if (v>array[m])
that should do the work but it actually doesn't.
You forget to retrive result of binary_search
:
if (array[m] == v)
return 1;
if (v > array[m])
return binary_search(array, v, m + 1, last);
return binary_search(array, v, first, m - 1);
I think you can simplify your code and select primary binary_search
mathod to accept an array
and required value
:
public static void main(String... args) {
int[] arr = { 1, 2, 4, 5, 6, 7, 8 };
int val = 4;
int pos = binarySearch(arr, val);
if (pos == -1)
System.out.format("Value %s was not found.\n", val);
else
System.out.format("Value %d was found at position %d\n", val, pos);
}
public static int binarySearch(int[] arr, int val) {
return binarySearch(arr, val, 0, arr.length - 1);
}
private static int binarySearch(int[] arr, int val, int left, int right) {
while (left <= right) {
int mid = (left + right) / 2;
if (arr[mid] == val)
return mid;
if (arr[mid] < val)
left = mid + 1;
else if (arr[mid] > val)
right = mid - 1;
}
return -1;
}