How to scan this line and use scan.skip()?

Question

I have a .txt file with lines of this format example : torch ; 3.0 ; 23.0

I want to scan it in order to place the first item in a String, and the second and third in a float.

Here is what I have done so far but the scan.skip(" ; ") doesn't work, I have also tried scan.skip(Pattern.compile(" ; ") but it didn't work either.

File file = new File(dir);
    try {
        Scanner scan = new Scanner(file);
        scan.skip(" ; ");
        scan.useDelimiter(Pattern.compile(" ; "));
        while (scan.hasNextLine()) {
            String s = scan.next();
            float f1 = scan.nextFloat();
            float f2 = scan.nextFloat();
        }
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }

Do you have any solutions for me ? Thanks

Answer 1

You may use ; or \n as delimiter and no need to skip, also I'd suggest to use Float.parseFloat(scan.next());

Scanner scan = new Scanner(file);
scan.useDelimiter(Pattern.compile("[;\\n]"));
while (scan.hasNextLine()) {
    String s = scan.next();
    float f1 = Float.parseFloat(scan.next());
    float f2 = Float.parseFloat(scan.next());
    System.out.println(s + " " + f1 + " " + f2);
}