Count and GROUP values from a CASE expression

Question

Trying to count the total number of wins and total times a horse finished in the top 6 and GROUP by the order of favouritism in a horse racing market.

I am referencing this answer since it is looking for a similar outcome Count the occurrences of DISTINCT values

I have tried this expression but when executed, it returns the same number in both case columns

ie;

SPFav   WinsByFavouritism   PlaceByFavouritism
1       4143                4143
2       3963                3963
3       3853                3853

This is the code I am running - what is causing this?

SELECT SPFav, 

COUNT(CASE WHEN FinishingPosition = 1 THEN 1 ELSE 0 END) as WinsByFavouritism,
COUNT(CASE WHEN FinishingPosition <= 6 THEN 1 ELSE 0 END) as PlaceByFavouritism

FROM [NRaceHistory].[dbo].[EachWayBetting]

GROUP BY SPFav 

ORDER BY SPFav ; 

Answer 1

Working with the first comment this would give the following possible solution.

Sample data

create table EachWayBetting
(
  SPFav int,
  FinishingPosition int
);

insert into EachWayBetting (SPFav, FinishingPosition) values
(1, 1),
(1, 2),
(1, 2),
(1, 9),
(2, 7),
(2, 8),
(2, 2),
(2, 1);

Solution

SELECT SPFav,
       COUNT(CASE WHEN FinishingPosition = 1 THEN 1 END) as WinsByFavouritism,
       COUNT(CASE WHEN FinishingPosition <= 6 THEN 1 END) as PlaceByFavouritism
FROM EachWayBetting
GROUP BY SPFav
ORDER BY SPFav

Result

SPFav WinsByFavouritism PlaceByFavouritism
----- ----------------- ------------------
1     1                 3
2     1                 2

Fiddle