Java BigDecimal long with decimal conversion

Question

I have a BigDecimal value of 123.45. I'd like to convert it to a long value of 12345 and I wonder what's the best way of doing this.

I'd rather avoid doing something like val.multiply(new BigDecimal(100)).toBigInteger()

Answer 1

Just posting this in case you want to know. Made a test for performances, as expected String replacement performed the worst.

results: movePointRight: 1230 multiply: 833 scaleByPowerOfTen: 591 String replacement: 3289

    BigDecimal val = new BigDecimal(0);
    long start = System.currentTimeMillis();
    for(int i = 0; i < 1000000; i++) {
        BigDecimal d = new BigDecimal(123.45);
        val = d.movePointRight(2);
    }
    long end = System.currentTimeMillis();
    System.out.println("movePointRight: " + (end - start));

    BigDecimal ten = new BigDecimal(10);
    start = System.currentTimeMillis();
    for(int i = 0; i < 1000000; i++) {
        BigDecimal d = new BigDecimal(123.45);
        val = d.multiply(new BigDecimal(100));
    }

    end = System.currentTimeMillis();
    System.out.println("multiply: " + (end - start));

    start = System.currentTimeMillis();
    for(int i = 0; i < 1000000; i++) {
        BigDecimal d = new BigDecimal(123.45);
        val = d.scaleByPowerOfTen(2);
    }

    start = System.currentTimeMillis();
    for(int i = 0; i < 1000000; i++) {
        BigDecimal d = new BigDecimal(123.45);
        val = d.scaleByPowerOfTen(2);
    }
    end = System.currentTimeMillis();
    System.out.println("scaleByPowerOfTen: " + (end - start));

    start = System.currentTimeMillis();
    for(int i = 0; i < 1000000; i++) {
        BigDecimal d = new BigDecimal(123.45);
        val =  new BigDecimal(d.toString().replace(".", ""));
    }
    end = System.currentTimeMillis();
    System.out.println("String replacement: " + (end - start));