Casting java primitives, does the JVM try to save memory?

Question

var foo = (short) 40 + (byte) 10

How many bytes does foo take up? What is its type?

I would expect that the result is stored in a short, but to save memory does the JVM test to see if it will fit in a smaller primitive?

If it were (short) 1 + (byte) 1 would it still be a short?

Answer 1

Rule of thumb: integer arithmetic operations are done as long and result in long if either argument is long, int otherwise.

I also suspect that the JVM uses 4 bytes even to store byte and short (and boolean) variables - see JVMS 2.6.1. Local Variables and Table 2.11.1-B.

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Even var test = (byte)1 + (byte)1 will cause test to be an int.

Not the case for var test = (byte)(1 + 1)