How can I make the 2 "print" give me true?
Code:
Config = {}
Config.option1.general = true
Config.option2.general = false
print(Config.option1.general)
print('Config.'..'option1'..'.general')
Output:
true
Config.option1.general
Excuse me for my ignorance
The objective was to create a function to which you give the option and execute a code with the variables of the corresponding list.
Just create a function that takes as input an option string, and use the string as a key into the Config
table:
function getOption (opt)
return Config[opt].general
end
Then you can use the returned value however you like:
> getOption('option1')
true
> print(getOption('option1'))
true
> if (getOption('option1')) then print 'Yay!' else print 'Aw...' end
Yay!
If you want to live dangerously, you can use load
to run a chunk of code from a string. Using this feature with user input is begging for security problems, though.
Just write a function that takes a string specifying the option, and use that input to fashion a string representing the chunk. The load
function returns a function that has the chunk as its body, so you will need to call that returned function to get the result from the chunk:
function getOption (opt)
local cmd = 'Config.' .. opt .. '.general'
return load('return ' .. cmd)()
end
With getOption('option1')
, the cmd
string becomes 'Config.option1.general'
, and this is concatenated with 'return '
to create the chunk 'return Config.option1.general'
which is passed to load
. The statement load('return Config.option1.general')()
calls the function returned by load
, and the returned value is returned again from the getOption
function.
Sample interaction:
> getOption('option1')
true
> getOption('option2')
false