JavaScript comparison operators issue : using 2 operators consecutively :why in JavaScript (12>11&&11>=10) does not equal to (12>11>=10)

Question

like normal math, I tried to log this code in the console and I expected to get the value true

 console.log(12>11>=10)

but what I got was false however when I tried to log console.log(12>11&&11>=10) I got true so for the last time, I tried console.log( (12>11&&11>=10) == (12>11>=10) )and i got flase

so my question is :

why in javascript (12>11&&11>=10) does not equal to (12>11>=10) ?!

and I hope anyone can help

Answer 1

Because programming language syntax and human intuition are two very different things. At no point will the language "know what you mean", you have to be completely explicit and unambigous.

What you have here are two operations. One using the > operator and one using the >= operator. Operations are atomic things. One will happen, then the other.

So this:

12 > 11

Results in this:

true

And then this:

true >= 10

Results in this:

false

Use less intuition and more logic. Separate your two operations:

12 > 11
11 >= 10

And combine them logically:

(12 > 11) && (11 >= 10)

Which will evaluate to:

true && true

Which will evaluate to:

true