c++hexbyteendianness
Does C++ std::hex reverse bytes order? (printing decimal as hexadecimal)
I'm having some trouble understanding the following C++ code:
std::cout << std::hex << 61183 << std::endl; // prints eeff
I'm working on a little-endian machine (Intel x86-64), and I wanted to understand, at bit and byte level, how that result is produced, so I wrote the following table for a least significant bit architecture.
As you can see, I expected the output of the line of code to be FFEE instead of EEFF. So I must have missed something while making that table, but I don't really see what. Is std::hex affected by the endianness of a computer?
Solution
Endianness is about how to store numbers in byte-addressed memory.
On the other hand, std::hex produces hexadecimal text.
0x1000 * 14 + 0x100 * 14 + 0x10 * 15 + 0x1 * 15 == 61183, so 61183 is EEFF in hexadecimal.
This won't be affected by endianness.
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