I need to check variadic arguments in std::enable_if
:
With C++17 I would write:
template <typename A, typename ...B>
class Foo : public A, public B...
{
public:
template <typename = std::enable_if_t<std::is_default_constructible_v<A> &&
(std::is_default_constructible_v<B> && ...)>>
Foo()
{}
Foo(A &&a, B && ... b)
: A(std::forward<A>(a)),
B(std::forward<B>(b))...
{}
};
But C++11 doesn't have a feature of expanding parameter packs this way. Neither does it provides std::conjunction
.
What is a simple way to implement conjunction with C++11? I suppose SFINAE with recursion would suffice, but I cannot wrap my hand around it.
You need a tool which will do the conjunction operation on variadic arguments.
#include <iostream>
#include <type_traits>
template<class...> struct conjunction : std::true_type { };
template<class B1> struct conjunction<B1> : B1 { };
template<class B1, class... Bn>
struct conjunction<B1, Bn...>
: std::conditional<bool(B1::value), conjunction<Bn...>, B1>::type {};
template <typename A, typename ...B>
class Foo : public A, public B...
{
public:
template <typename std::enable_if<std::is_default_constructible<A>::value &&
conjunction<std::is_default_constructible<B>...>::value, bool>::type = true>
Foo()
{}
Foo(A &&a, B && ... b)
: A(std::forward<A>(a)),
B(std::forward<B>(b))...
{}
};
struct A {};
struct B {};
struct C {
C(int x) {}
};
int main()
{
Foo<A, B> foo;
//Foo<A, B, C> bar;
return 0;
}
based on https://en.cppreference.com/w/cpp/types/conjunction which is available in C++17.