I would like to do something that probably is not possible in Cpp, but I could not find a post about this specifically.
I want to have a derived class specify the type of a void* parameter on a virtual function.
I have a base class called interface with a send function.
// pure virtual
class Interface{
virtual bool Send(const void*)=0;
};
struct Packet{
DataType data;
};
class SpecificInterface{
bool Send(const DataType*);
}
Is there a way to make something like this work? The intent is that SpecificInterface::Send implements Interface::Send. Allowing SpecificInterface to not be a pure virtual while restricting the void* to a specific packet type.
Otherwise I know I could take a void* parameter and static_cast it into the Packet* type; however, I do not want others to send a pointer type that cannot be cast to Packet*.
Let me know if this is not clear
@RSahu is correct, of course. You could still use a virtual method to do about the same thing:
class Interface {
virtual bool send(const void*) = 0;
};
struct Packet {
DataType data;
};
class SpecificInterface {
bool send(cont void*) override {
send(static_cast<DataType*>(data));
}
bool send(cont DataType*); // code which actually does something
};
However - I recommend against your whole approach to begin with - it is massively unsafe, since the validity of the type is never checked! It's a source of many potential bugs. More often than not, you can avoid doing this. Here are a few things you might try instead:
std::any
- a class which doesn't offer you compile-time type safety, but at least checks types at run-time. You would have a send(const std::any& data)
virtual function, and inside it you would call std::any_cast<DataType>(data)
to get a DataType
or std::any_cast<DataType>(&data)
to get a DataType *
.
Probably even better - the Curiously-recurring template pattern (CRTP):
template <typename T>
class Interface {
virtual bool send(T*) = 0;
};
class SpecificInterface : Interface<DataType> {
bool send(cont DataType*) override;
}