My debugging template is:
#define ts to_string
string ts(char c) { return string(1, c); }
string ts(bool b) { return b ? "true" : "false"; }
string ts(const char* s) { return (string)s; }
string ts(string s) { return s; }
template<class A> string ts(complex<A> c) {
stringstream ss; ss << c; return ss.str(); }
string ts(vector<bool> v) {
string res = "{"; for(int i = 0; i < si(v); ++i) res += char('0' + v[i]);
res += "}"; return res; }
template<size_t SZ> string ts(bitset<SZ> b) {
string res = ""; for(int i = 0; i < SZ; ++i) res += char('0' + b[i]);
return res; }
template<class A, class B> string ts(pair<A,B> p);
template<class T> string ts(T v) { // containers with begin(), end()
bool fst = 1; string res = "{";
for(const auto& x: v) {
if (!fst) res += ", ";
fst = 0; res += ts(x);
}
res += "}"; return res;
}
template<class A, class B> string ts(pair<A,B> p) {
return "(" + ts(p.f) + ", " + ts(p.s) + ")"; }
void DBG() { cerr << "]" << endl; }
template<class H, class... T> void DBG(H h, T... t) {
cerr << ts(h); if (sizeof...(t)) cerr << ", ";
DBG(t...); }
#ifdef LOCAL // compile with -DLOCAL
#define dbg(...) cerr << "[" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__)
#else
#define dbg(...) 0
#endif
When I type
dbg(a, n);
where 'a' is the vector name and n is the size of the vector. 'a' contains the following {1, 2, 3, 4, 5} and n = 5
it prints
[a, n]: [{1, 2, 3, 4, 5}, 5]
but I want it to print
[a]: [{1, 2, 3, 4, 5}]
[n]: [5]
without having to type
dbg(a);
dbg(n);
Is there any way to do this?
Codeforces community has helped me and told me the correct solution.
#define ts to_string
string ts(char c) { return string(1, c); }
string ts(bool b) { return b ? "true" : "false"; }
string ts(const char* s) { return (string)s; }
string ts(string s) { return s; }
template<class A> string ts(complex<A> c) {
stringstream ss; ss << c; return ss.str(); }
string ts(vector<bool> v) {
string res = "{"; for(int i = 0; i < si(v); ++i) res += char('0' + v[i]);
res += "}"; return res; }
template<size_t SZ> string ts(bitset<SZ> b) {
string res = ""; for(int i = 0; i < SZ; ++i) res += char('0' + b[i]);
return res; }
template<class A, class B> string ts(pair<A,B> p);
template<class T> string ts(T v) { // containers with begin(), end()
bool fst = 1; string res = "{";
for (const auto& x: v) {
if (!fst) res += ", ";
fst = 0; res += ts(x);
}
res += "}"; return res;
}
template<class A, class B> string ts(pair<A,B> p) {
return "(" + ts(p.f) + ", " + ts(p.s) + ")"; }
// DEBUG
void DBG(string names) { string s = names; }
template<class H, class... T> void DBG(string names, H h, T... t) {
auto pos = names.find(',');
auto first_name = names.substr(0, pos);
auto rest = names.substr(pos+1);
// Strip space at the beginning
while(rest.front() == ' '){
rest = rest.substr(1);
}
cerr << "[" << first_name << "]: [" << ts(h) << "]" << nl;
DBG(rest, t...);
}
#ifdef LOCAL
#define dbg(...) DBG(#__VA_ARGS__, __VA_ARGS__)
#else
#define dbg(...) 0
#endif
void EDBG() { cerr << "]" << endl; }
template<class H, class... T> void EDBG(H h, T... t) {
cerr << ts(h); if (sizeof...(t)) cerr << ", ";
EDBG(t...); }
#ifdef LOCAL // compile with -DLOCAL
#define edbg(...) cerr << "[" << #__VA_ARGS__ << "]: [", EDBG(__VA_ARGS__)
#else
#define edbg(...) 0
#endif
the macro
edbg
does not do it seperately so
edbg(a, n);
will output
edbg(a, n);
Whereas
dbg(a, n);
will output
dbg(a);
dbg(n);