C++ return value type (integer) does not match the function type

Question

#include <iostream>
#include <ctime>
using namespace std;


void randNum()
{
    int num1 = (rand() % 12) + 1;
    int num2 = (rand() % 12) + 1;
    int answer;
    answer = num1 * num2;

    return answer, num1, num2;
}
int main()
{
    srand(time(NULL));
}

I get the error return value type does not match the function type. Answer is an integer but it won't return regardless.

Answer 1

You can't return 3 things. You may wrap it in a struct if you wish. And make your function return the struct instead of void. In main, call your function

#include <iostream>
#include <ctime>
using namespace std;


struct three_values {
    int a;
    int b;
    int c;
};

three_values randNum()
{
    three_values return_me;
    int num1 = (rand() % 12) + 1;
    int num2 = (rand() % 12) + 1;
    int answer;
    answer = num1 * num2;
    return_me.a = num1;
    return_me.b = num2;
    return_me.c = answer;
    return return_me;
}

int main()
{
    srand(time(NULL));
    three_values var = randNum();

    std::cout << "num_1 = " << var.a << ", " << "num_2 = " << var.b << std::endl;
    std::cout << var.a << "*" << var.b << " = " << var.c << std::endl;
}

Possible output:

num_1 = 6, num_2 = 7                                                         
6*7 = 42