I have a raw string (created with the String.raw
method and template literal), which is supposed to contain several backslashes and backticks. Since the backticks are required to be escaped even in a raw string, I use backward slashes to escape them. Although, it does escape the backtick, the backward slash is also displayed along with it:
let rawString = String.raw`
__
/ |
\`| |
| |
_| |_
|_____|
`;
console.log(rawString);
So, while writing the question, I came up with an idea myself, and to my utmost surprise - it works!
Instead of using the backward slash for escaping, use ${...}
("placeholder" for string interpolation); like this:
let rawString = String.raw`
__
/ |
${"`"}| |
| |
_| |_
|_____|
`;
console.log(rawString);