I want to create a function that takes in a number and returns the {number} days prior to today, excluding weekends.
For example,
from datetime import date, timedelta
def get_date(days = 5):
today = date.today()
return today - timedelta(days)
when today is 2020-06-11, it should output 2020-06-04 (excluding 06-06 and 06-07).
Using only Python's built-in libraries:
from datetime import date, timedelta
def get_date(days = 5):
today = date.today()
if days == 0:
return today
retval = today
while days > 0:
retval -= timedelta(days=1)
if retval.weekday() not in [5,6]:
days -= 1
return retval