I have a string/integer X: 912035374356789
i want to check if X contains : 1, 2, 3, 4, 5, 6, 7, 8, 9, 0
occurrence order is not matter
How do check it using regular expression. if there is any algorithm please mention, because i want to do it in minimum time complexity
Example
ex1: 61243456092 //false 7 & 8 not present
ex2: 864123456789 //false 0 is not present
ex3: 987601234567 //true all present
If the string contains only digits then you can count the number of unique digits in it
long count = string.chars().distinct().count();
and check if count is 10
Example
String ex1 = "61243456092";
String ex2 = "864123456789";
String ex3 = "987601234567";
System.out.println(ex1.chars().distinct().count());
System.out.println(ex2.chars().distinct().count());
System.out.println(ex3.chars().distinct().count());
yields
8
9
10