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HTML / CSS Hide / Show Page Objects Without JavaScript Toggle Switch


How to use a single function to toggle multiple buttons/images. Here is what I have now for a demo. It only works for single button/images but I need to make multiple control.

body,
html {
  height: 100%;
}

#bg {
  background-image: url(http://basicblue.biz/treasure/treasuremap_01.jpg);
  height: 100%;
  width: 100%;
  background-position: center;
  background-repeat: no-repeat;
  background-size: 1080px 1080px;
  position: relative;
}

#menu {
  position: absolute;
  top: 50px;
  left: 50px;
  z-index: 100;
}

#menu button {
  background-color: lightblue;
  border: 1px solid white;
  color: darkblue;
  padding: 10px 24px;
  cursor: pointer;
  display: block;
}

#mark01 {
  position: absolute;
  top: 240px;
  right: 490px;
  z-index: 80;
}

#mark02 {
  position: absolute;
  top: 480px;
  left: 460px;
  z-index: 80;
}

#mark03 {
  position: absolute;
  bottom: 260px;
  right: 490px;
  z-index: 80;
}
<!DOCTYPE html>
<html>

<head>
  <meta name="viewport" content="width=device-width, initial-scale=1">
  <link rel="stylesheet" href="styles.css">
  <title>Treasure Map</title>
</head>

<body>

  <div id="menu">
    <button onclick="myMark01()">Marker 1</button>
    <button onclick="myMark02()">Marker 2</button>
    <button onclick="myMark03()">Marker 3</button>
  </div>

  <div id="bg">
    <img id="mark01" src="http://basicblue.biz/treasure/xmark_01.png">
    <img id="mark02" src="http://basicblue.biz/treasure/xmark_02.png">
    <img id="mark03" src="http://basicblue.biz/treasure/xmark_03.png">
  </div>

  <script>
    function myMark01() {
      var x = document.getElementById("mark01");
      if (x.style.display === "none") {
        x.style.display = "block";
      } else {
        x.style.display = "none";
      }
    }

    function myMark02() {
      var x = document.getElementById("mark02");
      if (x.style.display === "none") {
        x.style.display = "block";
      } else {
        x.style.display = "none";
      }
    }

    function myMark03() {
      var x = document.getElementById("mark03");
      if (x.style.display === "none") {
        x.style.display = "block";
      } else {
        x.style.display = "none";
      }
    }
  </script>

</body>

</html>

I want to do this with Pure HTML / CSS. Is it achievable or how to make this code more efficient.

So basically I need each button to control a different image layer allowing for individual control.

Thanks,


Solution

  • This is a bit limited, but if you can use a checkbox and want a pure HTML and CSS solution, you could use the :checked CSS selector as a reference for your CSS rules to hide/show elements whenever the box is checked.

    input:checked + .hidable {
      display: none;
    }
    
    input:not(:checked) + .showable {
      display: none;
    }
    <input type="checkbox" /> Hide text below
    <div class="hidable">I am totally not hidden right now</div><br />
    
    <input type="checkbox" /> Show some text below
    <div class="showable">It seems I just got shown</div><br />
    
    <input type="checkbox" /> Hide all the elements below, including image
    <div class="hidable">
      <strong>many elements here</strong>
      <strong>hi</strong>
      <img src="https://vignette.wikia.nocookie.net/rickandmorty/images/4/41/Garmanarnar.PNG/revision/latest?cb=20160117000927" />
      <strong>bye</strong>
    </div>

    Actually, there is a very nice example by MDN here.

    If you want to change the checkbox position in relation to the elements, you can play around with the selectors, like nth-child for instance, or you could use a grid layout - then you can place the checkbox wherever you like inside your grid template.