Search code examples
javaintbyteoverloading

Why 'int' by default, but not 'byte'?

Explain me please, why, when I write 4 overloaded methods and call it => it chooses method with 'int' as default, but not 'byte', which is closer/better, because it can storage values from -127 to 128?

class Main {
    public static void method(short s) {
        System.out.println("short");
    }

    public static void method(byte b) {
        System.out.println("byte");
    }

    public static void method(int i) {
        System.out.println("int");
    }

    public static void method(long l) {
        System.out.println("long");
    }

    public static void main(String[] args) {
        // put your code here
        method(10);
    }
}
Solution

  • Because the Java Language Specification says so.

    Section 3.10.1. Integer Literals says:

    An integer literal is of type long if it is suffixed with an ASCII letter L or l (ell); otherwise it is of type int (§4.2.1).

    So your numeric literal 10 is of type int.