My code:
#include <stdio.h>
#include <math.h>
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
char a[10],b[10];
puts("enter");
gets(a);
puts("enter");
gets(b);
puts("enter");
puts(a);
puts(b);
}
return 0;
}
Output:
1
enter
enter
surya (string entered by user)
enter
surya (last puts function worked)
How can I use “gets” function many times in C program?
You should never ever use gets()
in your program. It is deprecated because it is dangerous for causing buffer overflow as it has no possibility to stop consuming at a specific amount of characters - f.e. and mainly important - the amount of characters the buffer, a
or b
with each 10 characters, is capable to hold.
Also explained here:
Why is the gets function so dangerous that it should not be used?
Specially, in this answer from Jonathan Leffler.
Use fgets()
instead.
Also the defintion of a
and b
inside of the while
loop doesn´t make any sense, even tough this is just a toy program and for learning purposes.
Furthermore note, that scanf()
leaves the newline character, made by the press to return from the scanf()
call in stdin
. You have to catch this one, else the first fgets()
thereafter will consume this character.
Here is the corrected program:
#include <stdio.h>
int main()
{
int t;
char a[10],b[10];
if(scanf("%d",&t) != 1)
{
printf("Error at scanning!");
return 1;
}
getchar(); // For catching the left newline from scanf().
while(t--)
{
puts("Enter string A: ");
fgets(a,sizeof a, stdin);
puts("Enter string B: ");
fgets(b,sizeof b, stdin);
printf("\n");
puts(a);
puts(b);
printf("\n\n");
}
return 0;
}
Execution:
$PATH/a.out
2
Enter string A:
hello
Enter string B:
world
hello
world
Enter string A:
apple
Enter string B:
banana
apple
banana