How can I print the given pattern with just a loop and an inner loop? Instead of using 4 loops

Question

This is the code snippet, which should mark the Field of a Bishop (chess figure)
Sadly and obviously I am getting an array out of bounds exceptions - can someone solve the issue please?

int i = 1, j = 1;

 while (i <= 8) {
      board.markField(9-i, i);

      i++;

      while (j <= 8) {

          board.markField(j, i); // here is the error
          j++;      // j =2
          break;
      }
  }

Desired Output

o o o o o o o x
x o o o o o x o
o x o o o x o o
o o x o x o o o
o o o x o o o o
o o x o x o o o
o x o o o x o o
x o o o o o x o

It is not necessary, to help me with printing out the x or the o, I have a working function, that does this very good

 public void markField(int x, int y){

     board[x-1][y-1] = true;
 }

Answer 1

Two for-loops are enough to get it done, however, you will have to have some extra variables to get it done. Code:

int start = 0, end = 7;
boolean flag = false;
for(int i= 0; i<8; i++)
{
    if(i > 0)
        flag = true;
    for(int j= 0; j<8; j++)
    {
        if(flag && j==start)
        {
            //System.out.printf("x ");
            board.markField(i,j);
            start++;
            if(start == end+1)
                end--;
            flag = false;
            continue;
        }

        if(j==end)
        {
            //System.out.printf("x ");
            board.markField(i,j);
            end--;
            continue;
        }
        //System.out.printf("o ");
        board.markField(i,j);
    }
    //System.out.println();
}

As we are calling markField() with correct array indices, so, change your markField() like this:

public void markField(int x, int y){

 board[x][y] = true;
}