#include <iostream>
#include <boost/multiprecision/cpp_dec_float.hpp>
#include <boost/multiprecision/cpp_int.hpp>
using boost::multiprecision::number;
using boost::multiprecision::cpp_dec_float;
using boost::multiprecision::cpp_dec_float_50;
using boost::numeric_cast;
using std::cout;
int main()
{
srand(time(NULL));
std::cout << std::setprecision(std::numeric_limits<cpp_dec_float_50>::digits10);
cpp_dec_float_50 x = 0.0001;
cpp_dec_float_50 y = x*x*x*x;
std::cout << s << "\n";
}
So I followed the documentation here: https://www.boost.org/doc/libs/1_63_0/libs/multiprecision/doc/html/boost_multiprecision/tut/floats/cpp_dec_float.html
The output I expect to get is: 0.00000000000000000001 (20 zeros)
For the question, I just want to remove the "e^-16" part. How can I do that? In addition, if someone else can help me to output that exact values, it'd also be very helpful.
Thank you.
You've instantiated x
with a binary double value, which is not representable as a decimal. Here's how to fix that:
#include <iostream>
#include <boost/multiprecision/cpp_dec_float.hpp>
using boost::multiprecision::cpp_dec_float_50;
int main()
{
std::cout << std::setprecision(std::numeric_limits<cpp_dec_float_50>::digits10);
cpp_dec_float_50 x{"0.0001"};
cpp_dec_float_50 y = x*x*x*x;
std::cout << std::fixed;
std::cout << y << "\n";
}
Output:
0.00000000000000010000000000000000000000000000000000