I need to increment time in python and if the value of the range in loop increments, I need to set time to the original value.
example
start_time = '0230'
start_time = datetime.strptime(start_time, '%H%M')
difference_time = '0030'
difference_time = datetime.strptime(differece_time, '%H%M')
differnce_delta = timedelta(
hours=difference.hour, minutes=difference.minute)
listvar = [5, 3, 4]
for i in range(3):
x = listvar[i]
for loop in range(x)
print(f'{start_time.hour}:{start_time.minute}')
start_time += difference_delta
Now if the the value of i becomes 2, I want start_time to get back to original value i.e 0230.
You can use another variable as a place holder for the original value.
start_time = '0230'
start_time_holder = '0230'
start_time = datetime.strptime(start_time, '%H%M')
difference_time = '0030'
difference_time = datetime.strptime(differece_time, '%H%M')
differnce_delta = timedelta(
hours=difference.hour, minutes=difference.minute)
listvar = [5, 3, 4]
for i in range(5):
start_time = start_time_holder
x = listvar[i]
for loop in range(x):
print(f'{start_time.hour}:{start_time.minute}')
start_time += difference_delta
FYI: you would get a index out of range error at x = listvar[i] because the range is 5 but the list length is only 3