Angular / JS generate random Uniq Serial ID

Question

I'm creating a function that generate a random Uniq Serial id by replacing a string with this format ; xxxx-xxxx-xxxx-xxxx , the goal is to get a serial like that : ABCD-1234-EFGH-5678 ,the first and third parts are a letters and the second and last parts are numbers, this is my code :

public generateUniqSerial() {
   return 'xxxx-xxxx-xxx-xxxx'.replace(/[x]/g, function (c) {
     let r = Math.random() * 16 | 0, v = c == 'x' ? r : (r & 0x3 | 0x8)
     return v.toString(16)
   })
 }

it give a result like that : "7f8f-0d9a-fd5-450f" , how to edit this function to get a result with this format : ABCD-1234-EFGH-6789 ?

Answer 1

You can do something like this to generate a random Uniq Serial id with a format like ABCD-1234-EFGH-5678:

function rnd(t) {
  let str = '';
  const min = t === 'a' ? 10 : 0;
  const max = t === 'n' ? 10 : 62;
  for (let i = 0; i++ < 4;) {
    let r = Math.random() * (max - min) + min << 0;
    str += String.fromCharCode(r += r > 9 ? r < 36 ? 55 : 61 : 48);
  }
  return str;
}

function generateUniqSerial() {
  return `${rnd('a')}-${rnd('n')}-${rnd('a')}-${rnd('n')}`
}

console.log(generateUniqSerial())
console.log(generateUniqSerial())