firestore simple way to get one field in a document by function

Question

I am trying to return one field in a document. Is there a simple way to do this? This seems overkill:

let p = await (await this.afs.doc(`users/${uid}`).get().toPromise()).data()!.photoURL;

let p = await this.afs.doc(`users/${uid}`).ref.get().then((m) => { return m.data()!.photoURL; });

I was thinking something like this, but obviously it doesn't work:

let p = await this.afs.doc(`users/${uid}`).get('photoURL);

Any ideas?

Answer 1

This should be all that's needed:

let p = await (firebase.firestore().doc(`users/${uid}`).get()).get('photoURL');

The await (firebase.firestore().doc(users/${uid}).get()) awaits for the document to be loaded, and then then get('photoURL') gets the field.