In this project i'm aiming to do, when the user touches the screen, it prompt an actions to do, i have used QuickAction to do the action thing, but when i use onTouch, create a view with its x and y, give me the action view in wrong coordinates.
RelativeLayout mine;
QuickAction quickIntent;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mine = (RelativeLayout) LayoutInflater.from(EmptyActivity.this).inflate(R.layout.activity_empty, null, false);
setContentView(mine);
quickIntent = new QuickAction(EmptyActivity.this, QuickAction.HORIZONTAL);
quickIntent.addActionItem(new ActionItem(1, "Star", android.R.drawable.star_on));
quickIntent.addActionItem(new ActionItem(2, "Star", android.R.drawable.star_on));
quickIntent.addActionItem(new ActionItem(3, "Star", android.R.drawable.star_on));
}
@Override
public boolean onTouchEvent(MotionEvent event) {
int x = (int)event.getX();
int y = (int)event.getY();
if(event.getAction() == MotionEvent.ACTION_DOWN){
View v = new View(EmptyActivity.this);
v.setBackgroundColor(getResources().getColor(R.color.colorPrimary));
v.setLayoutParams(new LinearLayout.LayoutParams(5, 5));
v.setX(x);
v.setY(y);
mine.addView(v);
quickIntent.show(v);
return true;
}
return super.onTouchEvent(event);
}
As in the image, but when i increase the Y, its works fine.
v.setY(y-215);
Thanks.
When you touch on Activity window it giving y value with actionBar height.
So you have to subtract the actionBar height from y.
Code for ActiobBar height
final TypedArray styledAttributes = getBaseContext().getTheme().obtainStyledAttributes(
new int[] { android.R.attr.actionBarSize });
int mActionBarSize = (int) styledAttributes.getDimension(0, 0);
styledAttributes.recycle();
Now your y value will be
y = y-mActionBarSize;
To be more accurate TitleBar height is also need to subtract.