Split 1D Binary Array into 2D Array of Consecutive Ones Only

Question

Imagining I want to split a binary ID array arr into 2D array newArr of consecutive ones interspersed between zeros. Furthermore I want to collect the corresponding indices of the selected ones in a 2D array named Index.

arr = [1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 1, 1];

Expected results:

newArr = [[1, 1, 1] , [1, 1],[1, 1]];

Index = [[3,4,5], [7,8],[10,11]];

My attempt of this problem is attached, but is no good.

var arr = [1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 1, 1];

var newArr = [];
let i = arr.length
while(i--){
  if ((arr[i]===1) && (arr[i+1]===1)){
  	newArr.push(arr.splice(0,3));
  }
}

console.log(newArr)

Answer 1

You could reduce the array and collect the items which have a predecessor or a successor.

const
    getConnectedParts = array => array.reduce((r, v, i, a) => {
        if (!v || !a[i - 1] && !a[i + 1]) return r;
        if (!a[i - 1]) {
            r.values.push([]);
            r.indices.push([]);
        }
        r.values[r.values.length - 1].push(v);
        r.indices[r.indices.length - 1].push(i);
        return r;
    }, { values:[], indices: [] });

var array = [1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 1, 1],
    { values, indices } = getConnectedParts(array);

values.map(a => console.log(...a));
indices.map(a => console.log(...a));

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