Fizz Buzz question with extra difficulty layer

Question

I am trying to solve the Fizz Buzz question with an extra layer.

This is what I have so far. All this works fine but I need one more extra condition.

It's JS Unit testing

For any other input (valid or otherwise) return a string representation of the input

printFizzBuzz = function(input) {

  // Your code goes here
  for (var i = 1; i <= 20; i++) {

    if (i % 3 === 0 && i % 5 === 0) {
      console.log("FizzBuzz");
    } else if (i % 3 === 0) {
      console.log("FizzBuzz");
    } else if (i % 5 === 0) {
      console.log("Buzz");
    } else {
      console.log(i);
    }
  }
};

Thank you!

Answer 1

Looking at the question, it is not asking for a loop, it is asking for any value passed to the function. So the answer should look more like this

function printFizzBuzz(input) {

  // Your code goes here

  if (typeof input !== ‘number’) {
    return String(input)
  }

  let by3 = input % 3
  let by5 = input % 5

  switch(0) {
    case by3 + by5:
      return "FizzBuzz"

    case by3:
      return "Fizz"

    case by5:
      return "Buzz"

    default:
      return input.toString()
    }
  }
}