How do I parse the data I achieved through splitting a string into Int values in Java?

Question

I split a string which is a password entered by the user to only return back digits. I need to make sure those digits they entered aren't certain digits. But first, I need to take the data that comes back and turn them into an int so I can compare.

public static boolean checkPassword(String password){
      String digitsRegrex = "[a-zA-Z]+";
      int upPass;

      String [] splitPass = password.split("[a-zA-Z]+");
      for(String pass : splitPass){
         try{
            upPass = Integer.parseInt(pass);
         }
         catch (NumberFormatException e){
            upPass = 0;
         }       
         System.out.println(upPass);
      }  
      return true;   
  }

When I run the program I get back the 0 (and the digits in the string password) in the catch, so the try isn't working I guess?

Answer 1

In your code, you set upPass to 0 when you encounter a substring that do not contain any digits. These are empty strings. This happens when the password does not start with a digit.

You should be ignoring it as you need only digits.

Example: abcd12356zz33 - when you split using the regex [a-zA-Z]+ you get "", "123456", and "33". When you attempt to convert the first empty string to a number, you get a NumberFormatException.

for(String pass : splitPass){
    if (!pass.isEmpty()) {
        try {
            upPass = Integer.parseInt(pass);
            System.out.println(upPass);
            //Validate upPass for the combination of numbers
        } catch (NumberFormatException e) {
            throw e;
        }
    }
}

---

checkPassword("abcd12356zz33")

prints

12356
33