I need to use loop to find the sum of the following series:
(2/3)-(4/5)+(6/7)-(8/9)+......±n
I have to use for-loop only for this program. Refer the code to see what I've done:
import java.util.Scanner;
public class P64 {
public static void main(String args[]) {
Scanner sc=new Scanner(System.in);
System.out.println("Enter the limit");
double n=sc.nextDouble();
double sum=0;
for(double i=1;i<=n;i++) {
if(i%2==0)
sum=sum-(++i/i++);
else
sum=sum+(++i/i++);
}
System.out.println(sum);
}
}
I have tried this out but the output is either 1 or 0.
You should use a separate variable for values as using same in loop and your series will make it complex so, try this:
public static void main(String[] args){
Scanner sc=new Scanner(System.in);
System.out.println("Enter the limit");
double n=sc.nextDouble();
double sum=0;
double j=1;
for(double i=1;i<=n;i++)
{
if(i%2==0)
sum=sum-(++j/++j);
else
sum=sum+(++j/++j);
}
System.out.println(sum);
}
Input: 4 Output: -0.16507936507936516