Below code outputs:
Default ctor is called
Copy ctor is called
Default ctor is called
Copy ctor is called
Copy ctor is called
Why for each push_back()
the calling of copy constructor incremented by 1?
I think it should only be called one time.
Is there something which i miss here? please i need detailed explanation.
class A
{
public:
A()
{
std::cout << "Default ctor is called" << std::endl;
}
A(const A& other)
{
if(this != &other)
{
std::cout << "Copy ctor is called" << std::endl;
size_ = other.size_;
delete []p;
p = new int[5];
std::copy(other.p, (other.p)+size_, p);
}
}
int size_;
int* p;
};
int main()
{
std::vector<A> vec;
A a;
a.size_ = 5;
a.p = new int[5] {1,2,3,4,5};
vec.push_back(a);
A b;
b.size_ = 5;
b.p = new int[5] {1,2,3,4,5};
vec.push_back(b);
return 0;
}
This is because the push_back
in your example has to do a reallocation every time. If you reserve
the size in advance then you see only one copy.
std::vector<A> vec;
vec.reserve(10);