I can't print "enter" in Mips

Question

I'm converting C code to Mips code

The C code is

int main(void) {
int i;
int data [10] = { 10, -2, 5, 22, 99, 0, -5, 8, 30, 7};
    for(i=0; i<10; i++){
        printf("%d\n", data[i]);
       }
  return 0;
 }

my Mips code is

.data
    data: .space 10

    enter: .asciiz "\n"
.text
.globl main
main:
addi $s0, $zero, 10
add $t0, $zero, $zero
sw $s0, data($t0)

addi $s0, $zero, -2
addi $t0, $t0, 4
sw $s0, data($t0)

addi $s0, $zero, 5
addi $t0, $t0, 4
sw $s0, data($t0)

addi $s0, $zero, 22
addi $t0, $t0, 4
sw $s0, data($t0)

addi $s0, $zero, 99
addi $t0, $t0, 4
sw $s0, data($t0)

addi $s0, $zero, 0
addi $t0, $t0, 4
sw $s0, data($t0)

addi $s0, $zero, -5
addi $t0, $t0, 4
sw $s0, data($t0)

addi $s0, $zero, 8
addi $t0, $t0, 4
sw $s0, data($t0)

addi $s0, $zero, 30
addi $t0, $t0, 4
sw $s0, data($t0)

addi $s0, $zero, 7
addi $t0, $t0, 4
sw $s0, data($t0)

addi $t0, $zero, 0
Loop: slti $t1, $t0, 10
      beq $t1, $zero, Exit
      mul $t2, $t0, 4

      li $v0, 1
      lw $a0, data($t2)
      syscall

          li $v0, 4
      la $a0, enter
      syscall

      addi $t0, $t0, 1
      j Loop
Exit:




end:
li $v0, 10
syscall

s1 is for saving a value. t0 is for index t1 is a flag for slt t1 multiply 4 is t2

you should just focus on

          li $v0, 4
      la $a0, enter
      syscall

it prints 10-2522990-58307

dddddddddddddddddddddddddddddddddddasdfasdfasdfasdfasdfasdfasdf

plz help me dddddddddddddddddddddddddddddddddddddd

Answer 1

You haven't reserved enough memory for your data array. .space 10 reserves 10 bytes of memory, but you're trying to store 10 words (40 bytes). So you end up overwriting the newline character.

If you change the declaration to data: .space 40 you should get the expected output.