Handling fpu exception on windows

Question

I would like to handle fpu exception on windows, something like:

#include <math.h>
#include <fenv.h>
#include <stdio.h>

int main()
{
    double b = 0;
    int raised;
    feclearexcept (FE_ALL_EXCEPT);
    b /= 0;
    raised = fetestexcept (FE_OVERFLOW | FE_INVALID);
    if (raised & FE_OVERFLOW) { printf("over\n");}
    if (raised & FE_INVALID)  { printf("invalid\n");}

    return 0;
}

But on windows. I tried reading the MSDN, but the document is not clear at all. I want to do this with Visual Studio compilers, on both x86 and amd64 archs.

I am not interested in translating the exception in C++ - actually, I am not even interested in the FPU exception, only in knowing the FPU state after some computation, like the example above.

== edit ==

Ok, it looks like it is actually much simpler: using _clearfp is enough:

#include <math.h>
#include <float.h>
#include <stdio.h>

int main()
{
    double b = 0;
    int raised;
    raised = _clearfp();
    b /= 0;
    raised = _clearfp();
    if (raised & SW_INVALID)  { printf("invalid\n");}

    return 0;
}

Much better than dealing with exceptions, SEH and other non portable stuff :)

Answer 1

You can use _statusfp2() to retrieve the floating point status. Beware that 32-bit uses both FPU and SSE instructions. Some sample code:

#include "stdafx.h"
#include <float.h>
#include <math.h>
#include <assert.h>


int _tmain(int argc, _TCHAR* argv[])
{
  unsigned x86;
  unsigned sse;
  // Test zero-divide
  double d = 0;
  double v = 1 / d;
  _statusfp2(&x86, &sse);
  assert(x86 & _EM_ZERODIVIDE);
  // Test overflow
  v = pow(10, 310.0);
  _statusfp2(&x86, &sse);
  assert(sse & _EM_OVERFLOW);
  return 0;
}