I used "copy" to get two class variables. But when the latter function modifies the value of one of two variables, the other variable changes. How can I generate two independent variables?
Can't import other package like numpy to solve it. Thanks guys.
Question 200 in Leetcode, number of islands
input_list = [ [0, 1, 1, 1, 0],
[0, 1, 0, 1, 1],
[1, 1, 0, 0, 1],
[0, 0, 1, 0, 1]]
class Solution():
def __init__(self, input_list_ori):
self.island_count = 0
self.input_list = input_list_ori.copy()
# self.input_list_ori = [[0 for j in range(len(self.input_list[0]))]for i in range(len(self.input_list))]
self.input_list_ori = self.input_list.copy()
self.dirs = [[-1, 0], [0, 1], [0, -1], [1, 0]]
def find_connect_one(self):
assert(len(self.input_list) > 0)
for i_row in range(len(self.input_list[0])):
for i_col in range(len(self.input_list)):
if self.input_list[i_row][i_col] == 1:
self.island_count += 1
self.dfs(i_row, i_col)
return self.island_count, self.input_list_ori
def dfs(self, i_row, i_col):
self.input_list[i_row][i_col] = 0
self.input_list_ori[i_row][i_col] = self.island_count
for dir in self.dirs:
new_i_row = i_row+dir[0]
new_i_col = i_col+dir[1]
if new_i_row >= 0 and new_i_col >= 0 and new_i_row < len(self.input_list) and new_i_col < len(self.input_list[0]):
if self.input_list[new_i_row][new_i_col] == 1:
self.dfs(new_i_row, new_i_col)
solution = Solution(input_list)
print(len(input_list))
island_count, input_list_ori = solution.find_connect_one()
print(island_count)
def dfs(self, i_row, i_col):
self.input_list[i_row][i_col] = 0
self.input_list_ori[i_row][i_col] = self.island_count
I hope to get different value in these two list. Although I have generated them by "copy" operator, they always influence each other.
You should use copy.deepcopy
.
More explanations from the documentation:
A shallow copy constructs a new compound object and then (to the extent possible) inserts references into it to the objects found in the original.
A deep copy constructs a new compound object and then, recursively, inserts copies into it of the objects found in the original.
Your copy is creating a new list with reference to the internal list. Thus when you are modifying internal list, there are for the both list, self.input_list
, and self.input_list_ori
.