I am 3 days new to Python and I am trying to use findall() to search for a string character after a specified format
>>> nameRegex = re.compile(r'First Name: (.*?) Last Name: (.*?)')
>>> nameRegex.findall('This is my application for the job. First Name:
John Last Name: Johnson DOB 01/01/90')
>>> [('John', '')]
I realize I am using the non greedy ? in the group because otherwise it would return the DOB portion of the string as well.
Is there a way I could format to take the Johnson string portion and nothing more?
Since I am so new I am not sure which direction to move to get the desired portion of the string.
Thanks to anyone in advance.
Anchor your regex pattern with a space in the end. That should help you to capture everything after Last Name:
upto the next space
>>> nameRegex = re.compile(r'First Name: (.*?) Last Name: (.*?) ')
>>> nameRegex.findall('This is my application for the job. First Name: John Last Name: Johnson DOB 01/01/90')
[('John', 'Johnson')]