I need to be able to open a document using its default application in Windows and Mac OS. Basically, I want to do the same thing that happens when you double-click on the document icon in Explorer or Finder. What is the best way to do this in Python?
open
and start
are command-interpreter things for Mac OS/X and Windows respectively, to do this.
To call them from Python, you can either use subprocess
module or os.system()
.
Here are considerations on which package to use:
You can call them via os.system
, which works, but...
Escaping: os.system
only works with filenames that don't have any spaces or other shell metacharacters in the pathname (e.g. A:\abc\def\a.txt
), or else these need to be escaped. There is shlex.quote
for Unix-like systems, but nothing really standard for Windows. Maybe see also python, windows : parsing command lines with shlex
os.system("open " + shlex.quote(filename))
os.system("start " + filename)
where properly speaking filename
should be escaped, too.You can also call them via subprocess
module, but...
For Python 2.7 and newer, simply use
subprocess.check_call(['open', filename])
In Python 3.5+ you can equivalently use the slightly more complex but also somewhat more versatile
subprocess.run(['open', filename], check=True)
If you need to be compatible all the way back to Python 2.4, you can use subprocess.call()
and implement your own error checking:
try:
retcode = subprocess.call("open " + filename, shell=True)
if retcode < 0:
print >>sys.stderr, "Child was terminated by signal", -retcode
else:
print >>sys.stderr, "Child returned", retcode
except OSError, e:
print >>sys.stderr, "Execution failed:", e
Now, what are the advantages of using subprocess
?
'filename ; rm -rf /'
" problem, and if the file name can be corrupted, using subprocess.call
gives us little additional protection.retcode
in either case; but the behavior to explicitly raise an exception in the case of an error will certainly help you notice if there is a failure (though in some scenarios, a traceback might not at all be more helpful than simply ignoring the error).To the objection "But subprocess
is preferred." However, os.system()
is not deprecated, and it's in some sense the simplest tool for this particular job. Conclusion: using os.system()
is therefore also a correct answer.
A marked disadvantage is that the Windows start
command requires you to pass in shell=True
which negates most of the benefits of using subprocess
.