I have this number: 003859389453604802410207622210986832370060
. In this instance, I need to extract 07622210986832
which comes before 02
and ends with 37
.
In the real world, 07622210986832
is always 14 digits, and will always start with 02
and end with 37
BUT it could appear at any point in a string that is of random length - all we know is that the number will be there somewhere.
I'm currently using the formula:
=IF(LEN(IFERROR(REGEXEXTRACT(A1:A&"", "02(.*)37")))=14,
However, you will notice in the number sample there is another 02
- "024102".
This is causing an issue.
What I really want to happen is:
02
3
and 16 is 7
(37), that is the number we need.02
number with a 14 digit string and the next two numbers are not 37
- ignore.Use the pattern 02(\d{14})37
, it will extract a sequence of 14 digits preceded by 02
and followed by 37
.