I need to show all the users who have more than one ID but not return the users who do. I tried group by having but I need to list the IDs and not just count them so could not get that to work for me. I ended up with using a the code below but it returns all the records.
select id,fname,lname,ssn,dob count(id) over partition by fname,lname,ssn,dob) as cnt from TABLE order by cnt desc;
Use a subquery:
select id, fname, lname, ssn, dob
from (select id, fname, lname, ssn, dob,
count(id) over (partition by fname, lname, ssn, dob) as cnt
from TABLE
) t
where cnt >= 2
order by cnt;