How to create a directory in a function

Question

Editing:

I'm trying to build a simple function that print out a name, then creates a directory. I'm new at building function in bash, so I have the below script that didn't work:

dest_path=/home/all/todo    
line="name"

mkdir_for_name() {
echo $1
mkdir $2
}

mkdir_for_name $name
mkdir_for_name $dest_path/$name

What is wrong with that syntax?

Answer 1

Since you are using echo so I believe you want to print directory name; and off course you need to pass 2 arguments to your function. May be call your function in following way. In this way you need not to change your code.

mkdir_for_name  "$name"  "$dest_path/$name"

Complete script:

dest_path=/home/all/todo    
line="name"

mkdir_for_name() {
echo "$1"
mkdir "$2"
}

mkdir_for_name  "$name"  "$dest_path/$name"