How to get the index of the min value in an array using JavaScript?

Question

I wrote this function, which returns -1.

function sayHello() {
  let arrayEdificiosNiveis = [11,10,10];
  var indexMenor = arrayEdificiosNiveis.indexOf(Math.max(arrayEdificiosNiveis));
  console.log(indexMenor);
}
sayHello();

I expected 0, not -1. How do I solve this problem?

Answer 1

You need to spread the array for getting the maximum. Otherwise you get NaN as value (via a stringed array) and this is not in the array (and not searchable).

A spreaded array takes all elements as parameter for the function (spread syntax ...).

In this case it follows this way

Math.max(...[11, 10, 10])

is evaluated as

Math.max(11, 10, 10)

function sayHello() {
  arrayEdificiosNiveis = [11, 10, 10];
  var indexMenor = arrayEdificiosNiveis.indexOf(Math.max(...arrayEdificiosNiveis));
  
  console.log(indexMenor);
}

sayHello();

A single loop solution:

But why not use

v > a[r] ? i : r

(which feels more natural, sort of) instead of

v <= a[r] ? r : i

The problem is the first comparison with the first element at index zero. at this time, r = -1 and the element is a[r] = undefined.

A comparison with undefined and a relational operator of <, <=, > or >= is always false and that would return the wrong index of -1 instead of zero and this result does not change for any other element of the array.

const
    getFirstIndexOfMaxValue = array =>
        array.reduce((r, v, i, a) => v <= a[r] ? r : i, -1);            

console.log(getFirstIndexOfMaxValue([]));
console.log(getFirstIndexOfMaxValue([11]));
console.log(getFirstIndexOfMaxValue([11, 10]));
console.log(getFirstIndexOfMaxValue([11, 10, 10]));
console.log(getFirstIndexOfMaxValue([10, 11, 10]));
console.log(getFirstIndexOfMaxValue([10, 11, 10, 11]));