Java generics with parameter - inheritance

Question

I have the following code:

public class Inheritance {

    class A<T,U,V>{

    }

    class B<T,U,V> extends A<T,U,T>{        

    }
}

Could somebody explain me, how it actually works? Does the Class B extend only A class, which parameters are "T,U,T", or it extends the actual A"T,U,V" class?

Answer 1

Let put it into real example:

 public class Inheritance {
        public static class A<T,U,V>{
             T t;
             U u;
             V v;

             A(T t, U u, V v) {
                this.t = t;
                this.u = u;
                this.v = v;
            }

            T getT() {return t;}
            U getU() {return u;}
            V getV() {return v;}
        }

        public static class B<T,U,V> extends A<T,U,T>{
            public B(T t, U u, V v) {
                super(t, u ,t);
            }
        }

        public static void main(String[] args) {
            B<Boolean, Integer, String> b = new B<>(false, 1, "string");
           // 't' attribute is Boolean 
           // since type parameter T of class B is Boolean
           Boolean t = b.getT(); 
           // 'v' attribute is Boolean 
           // since type parameters T and V of class A must have the same type as 
           // type parameter T of class B 
           Boolean v = b.getV(); 
        }
    }

Basically class B extends class A (which has three generic params). By declaring B<T,U,V> extends A<T,U,T> you just bind the A's first and A's third generic param to the same type of B's first param

As shown in example in constructor of class B we have three distinct types - Boolean, Integer, String, but in constructor of class A we have only two distinct types Boolean, Integer because 1st and 3th constructor param of class A are both bound to Boolean type

More on generics and inheritence can be found here: https://docs.oracle.com/javase/tutorial/java/generics/inheritance.html