Switching an array's elements in C

Question

So i want to switch the elements of an array with 32 integers "n" times.

All elements should be on the next position and the last should be at the first.

I tried something like this:

while(scanf("%d", &n) != EOF)
{
    for(int j=0; j<n; j++)
    for(int i=1; i<31; i++)
    {
        t[0]=t[31];
        tmp=t[i];
        t[i]=t[i+1];
    }
}

Im not sure how could I use the tmp variable to solve this problem.

this is the array's element:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32

and it should look like this if the n=1:

32 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31

Answer 1

Your swap is wrong, it should look like this:

char temp = t[i];
t[i] = t[i + 1];
t[i + 1] = temp;

Also, if you want an infinite loop like this, I recommend skipping whitespace in the scanf, like this:

while (scanf(" %d", &n) == 1) // note the space before %d

All in all, this is how it could look like:

int main(int argc, char** argv) {
    char t[33] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ123456"; // 33 elements to leave space for '\0'
    int n;
    while (scanf(" %d", &n) == 1)
    {
        for (int j = 0; j < n; j++)
            for (int i = 0; i < 31; i++)
            {
                char temp = t[i];
                t[i] = t[i + 1];
                t[i + 1] = temp;
            }
        printf("string: %s\n", t);
    }
    return 0;
}