Operator Precedence - Expression Evaluation

Question

For the following code snippet I get the output as 1. I want to know how it came?

void main()
{
int x=10,y=20,z=5,i;
i=x<y<z;
printf("%d",i);
}

Answer 1

i=x<y<z;, gets interpreted as i=(x<y)<z, which in turn gets interpreted as i=1<z, which evaluates to 1.