I'm working on some homework and I need to create a function that checks if a value exists in a list. If it does it will return true, otherwise it returns false. I have an idea of how to do it but I keep getting errors. I think it may be due to my lack of knowledge of syntax and style as this is my first time coding in sml.
I created the function exist and am passing a value and list in as a tuple.
fun exist (x, []) =
if x = hd ([]) then true
else if x = tl ([]) then true
else false;
Sorry if this code is laughably incorrect but I get the error message:
" stdIn:2.6 Warning: calling polyEqual
stdIn:3.11 Warning: calling polyEqual
stdIn:1.6-4.11 Warning: match nonexhaustive
(x,nil) => ...
val exist = fn : ''a list * 'b list -> bool "
and I'm not really sure how to fix this. Any help would be great.
Your function is pattern-matching on []
, so it can only ever match the empty list.
Also, hd []
and tl []
are both errors since the empty list has neither head nor tail.
Further, if some_condition then true else false
is equivalent to some_condition
.
(And if some_condition then false else true
is equivalent to not some_condition
.)
Logical expressions are usually more readable than chains of conditionals.
And you forgot to recurse; you need to use exist
on the tail of the list if the first element is not what you're looking for.
Either stick to pattern matching:
fun exist (_, []) = false
| exist (x, y::ys) = x = y orelse exist (x, ys)
or don't use it:
fun exist (x, xs) = not (null xs) andalso (x = hd xs orelse exist (x, tl xs))
Pattern matching is often the most readable solution and gives a clear picture of the various cases.
(You seem to have mixed the two forms, treating []
as an identifier rather than a type constructor.)