I have a problem with creating a new column for multiple dataframes with a map function or a for-loop. I have 25 dataframes with cryptocurrency time series data:
ls(pattern="USD")
[1] "ADA.USD" "BCH.USD" "BNB.USD" "BTC.USD" "BTG.USD" "DASH.USD" "DOGE.USD" "EOS.USD" "ETC.USD" "ETH.USD" "IOT.USD"
[12] "LINK.USD" "LTC.USD" "NEO.USD" "OMG.USD" "QTUM.USD" "TRX.USD" "USDT.USD" "WAVES.USD" "XEM.USD" "XLM.USD" "XMR.USD"
[23] "XRP.USD" "ZEC.USD" "ZRX.USD"
Every object is a dataframe which stands for a cryptocurrency expressed in USD. And every dataframe has 2 columns: Date and Close (Closing price). For example: the dataframe "BTC.USD" stands for Bitcoin in USD:
head(BTC.USD)
# A tibble: 6 x 2
Date Close
1 2015-12-31 430.
2 2016-01-01 434.
3 2016-01-02 434.
4 2016-01-03 431.
5 2016-01-04 433.
Now I want to add a third column, which represents the daily return.
require(quantmod)
BTC.USD <- BTC.USD%>%mutate(Return= Delt(Close)*100)
For a single object (in this case Bitcoin [BTC.USD]) this code works as imagined:
> head(BTC.USD)
# A tibble: 6 x 3
Date Close Return[,"Delt.1.arithmetic"]
<date> <dbl> <dbl>
1 2015-12-31 430. NA
2 2016-01-01 434. 0.940
3 2016-01-02 434. -0.0622
4 2016-01-03 431. -0.696
5 2016-01-04 433. 0.608
6 2016-01-05 431. -0.489
Now I want to calculate the return for all 25 dataframes (or cryptocurrencies) with a map-function or a for-loop, but my code doesn't work:
temp = ls(pattern=".USD")
map(.x= temp,.f = mutate(Return= Delt(Close)*100))
Error in is.data.frame(.data) || is.list(.data) || is.environment(.data) : argument ".data" is missing, with no default
for (i in seq_along(temp)) {mutate(Return= Delt(Close)*100)}
Error in is.data.frame(.data) || is.list(.data) || is.environment(.data) : argument ".data" is missing, with no default
Can someone help me?
First, we need to actually get the data as a list (each data.frame
will get its own entry in the list). Then, we can use any of our favorite list iterating functions to get the desired result.
temp_data <- lapply(ls(pattern = "USD"), get) # get data into a list
temp_data2 <- lapply(temp_data, function(x) mutate(x, Return = Delt(Close)*100))
As @akrun noted, there is a more compact way to do this:
lapply(mget(ls(pattern = "USD")), transform, Return = Delt(Close) * 100)
If you want to stick with tidyverse
verbs, that would be:
lapply(mget(ls(pattern = "USD")), function(x) x %>% mutate(Return = Delt(Close) * 100))
I could get the code to work using your sample data:
sdat1 <-structure(list(
Date = c("2015-12-31","2016-01-01",
"2016-01-02","2016-01-03","2016-01-04"),
Close = c(430, 434, 434, 431, 433)),
class = "data.frame",
row.names = c("1", "2", "3", "4", "5"))
sdat4 <- sdat3 <- sdat2 <- sdat1
lapply(mget(ls(pattern = 'sdat')),
FUN = function(x) x %>% mutate(Return = Delt(Close)))