I need an example of how to Broadcast same message to multiple receivers using EasyNetQ library

Question

I am trying to use EasyNetQ to send and receive messages from RabbitMQ, I need to send same message to multiple receivers or whom ever is connected at the time.

I have tried publish-subscribe messaging pattern and it works fine, but it's more like round-robin, where once the message is received by a receiver it's removed from the queue and nobody else can see the message.

Here's my message sender.

        for (int i = 0; i < 10; i++)
        {
            using (IBus bus = RabbitHutch.CreateBus(Host))
            {
                bus.Publish(new TextMessage { Text = $"{i}: Hello World from EasyNetQ" }, "dashboard");
            }
        }

Here's my receiver.

public void GetMessages() {

        using (IBus bus = RabbitHutch.CreateBus(Host))
        {
            bus.Subscribe<TextMessage>("dashboard", HandleTextMessage);

            Console.WriteLine("Listening for messages. Hit <return> to quit.");
            Console.ReadLine();
        }
    }

    static void HandleTextMessage(TextMessage textMessage)
    {
        Console.ForegroundColor = ConsoleColor.Red;
        Console.WriteLine("Got message: {0}", textMessage.Text);
        Console.ResetColor();
    }

Once a message is received no other receiver can see that message and I need all of the connected receivers see the same message.

Answer 1

I did not understand how RabbitMQ works. All I needed was to create an Exchange and have Exchange send the messages to the queues. I though Queues did that.