__FILE__ returns different value when using binding.pry

Question

__FILE__ returns the path of the current Ruby script file.

One potentially significant problem is that, if using binding.pry, __FILE__ evaluates to (pry). It is potentially problematic to have __FILE__ evaluate to different values depending on whether it is evaluated in the context of binding.pry. For example,

$stdout.print "****************************************\n\n"
$stdout.print "FILE: #{__FILE__}\n\n"
$stdout.print "****************************************\n\n"

binding.pry

When the script pauses at binding.pry, I get:

__FILE__
# >> (pry)

Does anyone know any mechanism to get the path of the current file even in the context of binding.pry?

Answer 1

Use _file_ instead of __FILE__. For example, given two files:

# foo.rb
require 'pry'
require './bar'
binding.pry
b = Bar.new

and:

# bar.rb
require 'pry'
class Bar
  def initialize
    binding.pry
  end
end

Run them with ruby foo.rb:

ruby foo.rb

From: /Users/username/foo.rb @ line 3 :

    1:     require 'pry'
    2:     require './bar'
 => 3:     binding.pry
    4:     b = Bar.new

(main):1 ⇒ _file_
=> "/Users/username/foo.rb"
(main):2 ⇒ exit

From: /Users/username/bar.rb @ line 4 Bar#initialize:

    3: def initialize
 => 4:   binding.pry
    5: end

(#<Bar:0x00007fbb6caaff08>):1 ⇒ _file_
=> "/Users/username/bar.rb"

_file_ and any other local variable names can be found in binding.local_variables.