I have the following code which works fine:
auto my_time = std::chrono::system_clock::now();
std::cout << "My Time is " << std::chrono::system_clock::to_time_t(my_time) << std::endl;
However, if I replace system_clock with high_resolution_clock like below:
auto my_time = std::chrono::high_resolution_clock::now();
std::cout << "My Time is " << std::chrono::high_resolution_clock::to_time_t(my_time) << std::endl;
I got the following error:
no member named 'to_time_t' in 'std::__1::chrono::steady_clock'
std::cout << "My Time is " << std::chrono::high_resolution_clock::to_time_t(my_time) << std::endl;
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^
1 error generated.
Any idea how to make high_resolution_clock works here? (I am benchmarking some functions, so would like to use high_resolution_clock rather than system_clock) Thanks!
On your system, high_resolution_clock is aliased to steady_clock, which is not required by the standard to implement to_time_t. It's possible that the two are incompatible, e.g. if time_t is seconds since epoch, and high_resolution_clock::period is smaller than 1 second, then you couldn't represent a high_resolution_clock::time_point as a time_t without a loss of precision.
If you are using this for benchmarking, you can probably skip the conversion to time_t altogether. Just do something like:
auto start = std::chrono::high_resolution_clock::now();
my_function();
auto end = std::chrono::high_resolution_clock::now();
std::cout << "my_function took " << std::chrono::duration_cast<std::chrono::milliseconds>(end - start).count() << " ms" << std::endl;