There seems to be an issue when using shared pointers together with a custom equality operator and an std::list.
I put together the following example code to demonstrate the issue.
Before trying to compile this:
I'm using gcc version 4.5.2 20110127
with the following commandline:
g++ -g -O0 -std=gnu++0x test.cpp
The source won't compile if c++0x features aren't enabled.
#include<list>
#include<boost/shared_ptr.hpp>
using std::list;
using std::shared_ptr;
using std::cout;
using std::endl;
class TestInt
{
public:
TestInt(int x);
bool operator==(const TestInt& other);
private:
int _i;
};
TestInt::TestInt(int x)
{
_i = x;
}
bool
TestInt::operator==(const TestInt& other)
{
if (_i == other._i){
return true;
}
return false;
}
class Foo
{
public:
Foo(TestInt i);
shared_ptr<TestInt> f(TestInt i);
private:
list<shared_ptr<TestInt>> _x;
};
Foo::Foo(TestInt i)
{
_x.push_back(shared_ptr<TestInt>(new TestInt(i)));
};
shared_ptr<TestInt>
Foo::f(TestInt i)
{
shared_ptr<TestInt> test(new TestInt(i));
int num = _x.size();
list<shared_ptr<TestInt>>::iterator it = _x.begin();
for (int j=0; j<num; ++j){
if (test == *it){
return test;
}
++it;
}
throw "Error";
}
int main(){
TestInt ti(5);
TestInt ti2(5);
Foo foo(ti);
foo.f(ti2);
std::cout << "Success" << std::endl;
}
I would have expected that the code finishes with Success
but instead it throws.
Inserting a *
infront of test
as well as *it
fixes the issue but my understanding is that when the shared_ptr calles __a.get() == __b.get()
in its ==
operator it should use the custom equality operator of TestInt
. I don't understand why it is not. Is this a bug?
Thanks in advance.
This is because when you compare two shared_ptr<T>
, you are comparing the reference, that is, the memory address that the two instances point to, not the underlying values.